Chemistry · 2021
JEE Main · 25 February 2021, Shift 2 · Q32
The solubility of Ca ( OH )_2 in water is: [Given: The solubility product of Ca ( OH )_2 in water =5.5 × 10^-6 ]
The solubility of $\displaystyle \mathrm{Ca}(\mathrm{OH})_2$ in water is :
[Given : The solubility product of $\displaystyle \mathrm{Ca}(\mathrm{OH})_2$ in water $\displaystyle =5.5 \times 10^{-6}$ ]
Official answer
(1)
$\displaystyle 1.11 \times 10^{-2}$
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.