The product ( C ) in the below mentioned reaction is: CH_3- CH_2- CH_2- Br →[Δ] KOH_( alc ) A → HBr B →[ KOH_( aq ) ] Δ C

The product $\displaystyle (\mathrm{C})$ in the below mentioned reaction is : $$\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br} \xrightarrow[\Delta]{\mathrm{KOH}_{(\mathrm{alc})}} \mathrm{A} \xrightarrow{\mathrm{HBr}} \mathrm{~B} \xrightarrow[\mathrm{KOH}_{(\mathrm{aq})}]{\Delta} \mathrm{C} $$