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Chemistry · 2018
JEE Main 2018 · 2018-04-08 Offline · Q47
The oxidation states of Cr in [ Cr ( H_2 O )_6] Cl_3,[ Cr ( C_6 H_6)_2], and K_2[ Cr ( CN )_2( O )_2( O_2)( NH_3)] respectively are:
The oxidation states of Cr in $\displaystyle \left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3,\left[\mathrm{Cr}\left(\mathrm{C}_6 \mathrm{H}_6\right)_2\right]$, and $\displaystyle \mathrm{K}_2\left[\mathrm{Cr}(\mathrm{CN})_2(\mathrm{O})_2\left(\mathrm{O}_2\right)\left(\mathrm{NH}_3\right)\right]$ respectively are :
Official answer
(3)
+$\displaystyle 3$, $\displaystyle 0$, and +$\displaystyle 6$
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JEE Main 2018 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.