Chemistry · 2022
JEE Main · 26 July 2022, Shift 2 · Q86
The number of non-ionisable protons present in the product B obtained from the following reactions is \ \ \ \. C_2 H_5 OH + PCl_3 → C_2 H_5 Cl + A; A…
The number of non-ionisable protons present in the product B obtained from the following reactions is \_\_\_\_.
$$\begin{aligned}
& \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{PCl}_3 \rightarrow \mathrm{C}_2 \mathrm{H}_5 \mathrm{Cl}+\mathrm{A} \\
& \mathrm{~A}+\mathrm{PCl}_3 \rightarrow \mathrm{~B}
\end{aligned}
$$
Official answer
2
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.