Chemistry · 2020
JEE Main · 7 January 2020, Shift 2 · Q50
The number of sp^2 hybridised carbons present in "Aspartame" is \ \ \ \.
The number of $\displaystyle \mathrm{sp}^2$ hybridised carbons present in "Aspartame" is \_\_\_\_.
Official answer
9
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.