Chemistry · 2022
JEE Main · 25 July 2022, Shift 1 · Q89
The number of sp^3 hybridised carbons in an acyclic neutral compound with molecular formula C_4 H_5 N is \ \ \ \.
The number of $\displaystyle \mathrm{sp}^3$ hybridised carbons in an acyclic neutral compound with molecular formula $\displaystyle \mathrm{C}_4 \mathrm{H}_5 \mathrm{~N}$ is \_\_\_\_.
Official answer
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.