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Chemistry · 2021

JEE Main · 26 August 2021, Shift 1 · Q58

The number of 4 f electrons in the ground state electronic configuration of Gd^2+ is \ \ \ \. [Atomic number of Gd =64 ]

The number of $\displaystyle 4 f$ electrons in the ground state electronic configuration of $\displaystyle \mathrm{Gd}^{2+}$ is \_\_\_\_. [Atomic number of $\displaystyle \mathrm{Gd}=64$ ]
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.