Chemistry · 2022
JEE Main · 29 June 2022, Shift 1 · Q90
C_6 H_12 O_6 → Zymase A →[Δ] NaOI B + CHI_3 The number of carbon atoms present in the product B is \ \ \ \.
$$\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6 \xrightarrow{\text { Zymase }} \mathrm{A} \xrightarrow[\Delta]{\mathrm{NaOI}} \mathrm{~B}+\mathrm{CHI}_3
$$
The number of carbon atoms present in the product B is \_\_\_\_.
Official answer
1
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.