Chemistry · 2025
JEE Main · 22 January 2025, Shift 2 · Q52
The molar solubility(s) of zirconium phosphate with molecular formula ( Zr^4+)_3( PO_4^3-)_4 is given by relation:
The molar solubility(s) of zirconium phosphate with molecular formula $\displaystyle \left(\mathrm{Zr}^{4+}\right)_3\left(\mathrm{PO}_4^{3-}\right)_4$ is given by relation :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \left(\frac{\mathrm{K}_{\mathrm{sp}}}{6912}\right)^{\frac{1}{7}}$
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.