Chemistry · 2019
JEE Main · 9 April 2019, Shift 1 · Q31
The major product of the following reaction is: CH_3 CH = CHCO_2 CH_3 → LiAlH_4
The major product of the following reaction is :
$$\mathrm{CH}_3 \mathrm{CH}=\mathrm{CHCO}_2 \mathrm{CH}_3 \xrightarrow{\mathrm{LiAlH}_4}
$$
Official answer
(2)
$\displaystyle \mathrm{CH}_3 \mathrm{CH}=\mathrm{CHCH}_2 \mathrm{OH}$
All Carboxylic Acids and Their Derivatives questionsPractice Carboxylic Acids and Their Derivatives →
More from Carboxylic Acids and Their Derivatives
- Which of the following derivatives of alcohols is unstable in an aqueous base?2020
- The major product formed in the following reaction is:2023
- The major product ' P ' formed in the given reaction is2023
- The most suitable reagent for the given conversion is:2020
- The total number of compounds from below when treated with hot KMnO_4 giving benzoic acid is:2025
- The product in the following sequence of reactions has ____ π bonds.2024
- Major product B of the following reaction has ____ π -bond.2024
- Number of compounds from the following which will not dissolve in cold NaHCO_3 and NaOH solutions but will dissolve in hot NaOH solution is ____2023
JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.