Chemistry · 2021
JEE Main · 25 February 2021, Shift 1 · Q57
The ionization enthalpy of Na^+ formation from Na_( g ) is 495.8 kJ mol^-1, while the electron gain enthalpy of Br is -325.0 kJ mol^-1. Given the…
The ionization enthalpy of $\displaystyle \mathrm{Na}^{+}$ formation from $\displaystyle \mathrm{Na}_{(\mathrm{g})}$ is $\displaystyle 495.8 \mathrm{~kJ} \mathrm{~mol}^{-1}$, while the electron gain enthalpy of Br is $\displaystyle -325.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Given the lattice enthalpy of NaBr is $\displaystyle -728.4 \mathrm{~kJ} \mathrm{~mol}^{-1}$. The energy for the formation of NaBr ionic solid is (-) \_\_\_\_ $\displaystyle \times 10^{-1} \mathrm{~kJ} \mathrm{~mol}^{-1}$.
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