The equilibrium composition for the reaction PCl_3+ Cl_2 ⇌ PCl_5 at 298 K is given below: [ PCl_3]_eq =0.2 mol L^-1,[ Cl_2]_eq =0.1 mol L^-1,[…

The equilibrium composition for the reaction $\displaystyle \mathrm{PCl}_3+\mathrm{Cl}_2 \rightleftharpoons \mathrm{PCl}_5$ at $\displaystyle 298$ K is given below: $\displaystyle \left[\mathrm{PCl}_3\right]_{\mathrm{eq}}=0.2 \mathrm{~mol} \mathrm{~L}^{-1},\left[\mathrm{Cl}_2\right]_{\mathrm{eq}}=0.1 \mathrm{~mol} \mathrm{~L}^{-1},\left[\mathrm{PCl}_5\right]_{\mathrm{eq}}=0.40 \mathrm{~mol} \mathrm{~L}^{-1}$ If $\displaystyle 0.2$ mol of $\displaystyle \mathrm{Cl}_2$ is added at the same temperature, the equilibrium concentrations of $\displaystyle \mathrm{PCl}_5$ is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$Given: $\displaystyle \mathrm{K}_{\mathrm{c}}$ for the reaction at $\displaystyle 298$ K is $\displaystyle 20$