Chemistry · 2019
JEE Main · 10 April 2019, Shift 2 · Q48
The crystal field stabilization energy (CFSE) of [ Fe ( H_2 O )_6] Cl_2 and K_2[ NiCl_4], respectively, are:
The crystal field stabilization energy (CFSE) of $\displaystyle \left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_2$ and $\displaystyle \mathrm{K}_2\left[\mathrm{NiCl}_4\right]$, respectively, are:
Official answer
(2)
$\displaystyle -0.4 \Delta_{\mathrm{o}} \text { and }-0.8 \Delta_{\mathrm{t}}$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.