Chemistry · 2019
JEE Main · 11 January 2019, Shift 2 · Q48
The coordination number of Th in K_4[ Th ( C_2 O_4)_4( OH_2)_2] is: ( C_2 O_4^2-= Oxalato )
The coordination number of Th in $\displaystyle \mathrm{K}_4\left[\operatorname{Th}\left(\mathrm{C}_2 \mathrm{O}_4\right)_4\left(\mathrm{OH}_2\right)_2\right]$ is :
$$\left(\mathrm{C}_2 \mathrm{O}_4^{2-}=\text { Oxalato }\right)
$$
Official answer
(3)
$\displaystyle 10$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.