1 L, 0.02 M solution of [ Co ( NH_3)_5 SO_4] Br is mixed with 1 L, 0.02 M solution of [ Co ( NH_3)_5 Br ] SO_4. The resulting solution is divided…

$\displaystyle 1 \mathrm{~L}, 0.02 \mathrm{M}$ solution of $\displaystyle \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{SO}_4\right] \mathrm{Br}$ is mixed with $\displaystyle 1 \mathrm{~L}, 0.02 \mathrm{M}$ solution of $\displaystyle \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}\right] \mathrm{SO}_4$. The resulting solution is divided into two equal parts (X) and treated with excess of $\displaystyle \mathrm{AgNO}_3$ solution and $\displaystyle \mathrm{BaCl}_2$ solution respectively as shown below: $\displaystyle 1$ L Solution (X) $\displaystyle +\mathrm{AgNO}_3$ solution (excess) ⟶ Y $\displaystyle 1$ L Solution (X) $\displaystyle +\mathrm{BaCl}_2$ solution (excess) ⟶ Z The number of moles of Y and Z respectively are