Chemistry · 2022
JEE Main · 27 June 2022, Shift 1 · Q68
BeCl_2 reacts with LiAlH_4 to give:
$\displaystyle \mathrm{BeCl}_2$ reacts with $\displaystyle \mathrm{LiAlH}_4$ to give :
Official answer
(3)
$\displaystyle \mathrm{BeH}_2+\mathrm{LiCl}+\mathrm{AlCl}_3$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.