Chemistry · 2021
JEE Main · 4 August 2021, Shift 2 · Q42
Reaction of CH_3- CH = CH_2 with different reagents (List-I) yield different products (List-II). Match List-I with List-II: The correct match is:
Reaction of $\displaystyle \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2$ with different reagents (List-I) yield different products (List-II).
Match List-I with List-II :
The correct match is :
| List-I : Reagents | List-II : Products on reaction with $\displaystyle \mathbf{C H}_{\mathbf{3}}-\mathbf{C H}=\mathbf{C H}_{\mathbf{2}}$ |
| A. $\displaystyle \mathrm{O}_3 / \mathrm{Zn}, \mathrm{H}_2 \mathrm{O}$ | I. Ethanoic acid |
| B. $\displaystyle \mathrm{KMnO}_4 / \mathrm{H}_2 \mathrm{SO}_4$ | II. Propan-$\displaystyle 2$-ol |
| C. $\displaystyle \mathrm{KMnO}_4 / \mathrm{NaOH}$ | III. Ethanal |
| D. $\displaystyle \mathrm{H}_3 \mathrm{O}^{+}$ | IV. Propane-$\displaystyle 1$, $\displaystyle 2$-diol |
Official answer
(1)
A-III, B-I, C-IV, D-II
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.