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Chemistry · 2023

JEE Main · 29 January 2023, Shift 2 · Q46

Reaction of propanamide with Br_2 / KOH ( aq ) produces:

Reaction of propanamide with $\displaystyle \mathrm{Br}_2 / \mathrm{KOH}(\mathrm{aq})$ produces :
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JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.