Chemistry · 2020
JEE Main · 6 September 2020, Shift 2 · Q37
Reaction of an inorganic sulphite X with dilute H_2 SO_4 generates compound Y. Reaction of Y with NaOH gives X. Further, the reaction of X with Y and…
Reaction of an inorganic sulphite $\displaystyle X$ with dilute $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ generates compound Y . Reaction of Y with NaOH gives X . Further, the reaction of $\displaystyle X$ with $\displaystyle Y$ and water affords compound Z. Y and Z, respectively, are :
Official answer
(2)
$\displaystyle \mathrm{SO}_2$ and $\displaystyle \mathrm{NaHSO}_3$
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.