Chemistry · 2023
JEE Main · 24 January 2023, Shift 2 · Q48
K_2 Cr_2 O_7 paper acidified with dilute H_2 SO_4 turns green when exposed to
$\displaystyle \mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ paper acidified with dilute $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ turns green when exposed to
Official answer
From NTA’s final answer key for this paper.
(4)
Sulphur dioxide
More from Qualitative Salt Analysis
- Consider the following test for a group-IV cation. M^2++H_2 S → A( Black precipitate )+ byproduct; A+ aqua regia → B+NOCl+S+H_2 O; B+KNO_2+CH_3 COOH…2024
- Molar mass of the salt from NaBr, NaNO_3, KI and CaF_2 which does not evolve coloured vapours on heating with concentrated H_2 SO_4 is ____ g mol^-1.…2024
- Match List I with List II Choose the correct answer from the options given below:2024
- Consider the following reactions Na_2 B_4 O_7 →Δ 2 X+Y; CuSO_4+Y → Non-Luminous flame Z+SO_3; 2 Z+2 X+ Carbon → Luminous flame 2 Q+Na_2 B_4 O_7+CO…2026
- In the precipitation of the iron group (III) in qualitative analysis, ammonium chloride is added before adding ammonium hydroxide to:2024
- Formulae for Nessler's reagent is:2023
- When a salt is treated with sodium hydroxide solution it gives gas X. On passing gas X through reagent Y a brown coloured precipitate is formed. X…2025
- During the qualitative analysis of SO_3^2- using dilute H_2 SO_4, SO_2 gas is evolved which turns K_2 Cr_2 O_7 solution (acidified with dilute H_2…2023
JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.