Chemistry · 2021
JEE Main · 25 July 2021, Shift 2 · Q58
Number of electrons present in 4 f orbital of Ho^3+ ion is \ \ \ \. (Given Atomic No. of Ho =67)
Number of electrons present in $\displaystyle 4$ f orbital of $\displaystyle \mathrm{Ho}^{3+}$ ion is \_\_\_\_. (Given Atomic No. of $\displaystyle \mathrm{Ho}=67)$
Official answer
10
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