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Chemistry · 2021

JEE Main · 22 July 2021, Shift 2 · Q31

Match List - I with List - II: Choose the correct answer from the options given below:

Match List - I with List - II :
List - IList - II
(Species)(Hybrid Orbitals)
(a)$\displaystyle \mathrm{SF}_4$(i)$\displaystyle \mathrm{sp}^3 \mathrm{~d}^2$
(b)$\displaystyle \mathrm{IF}_5$(ii)$\displaystyle \mathrm{d}^2 \mathrm{sp}^3$
(c)$\displaystyle \mathrm{NO}_2^{+}$(iii)$\displaystyle \mathrm{sp}^3 \mathrm{~d}$
(d)$\displaystyle \mathrm{NH}_4^{+}$(iv)$\displaystyle \mathrm{sp}^3$
(v)sp
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.