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Chemistry · 2024

JEE Main · 6 April 2024, Shift 2 · Q64

Match List - I with List - II. Choose the correct answer from the options given below:

Match List - I with List - II.
List - IList - II
ReactionType of redox reaction
(A)$\displaystyle \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NO}_{(\mathrm{g})}$(I)Decomposition
(B)$\displaystyle 2 \mathrm{~Pb}\left(\mathrm{NO}_3\right)_{2(\mathrm{~s})} \rightarrow 2 \mathrm{PbO}_{(\mathrm{s})}+4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$(II)Displacement
(C)$\displaystyle 2 \mathrm{Na}_{(\mathrm{s})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} \rightarrow 2 \mathrm{NaOH}_{(\mathrm{aq} .)}+\mathrm{H}_{2(\mathrm{~g})}$(III)Disproportionation
(D)$\displaystyle 2 \mathrm{NO}_{2(\mathrm{~g})}+2^{-} \mathrm{OH}(\mathrm{aq}.) \rightarrow \mathrm{NO}_{2(\mathrm{aq} .)}^{-}+\mathrm{NO}_{3(\mathrm{aq} .)}^{-}+\mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}$(IV)Combination
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.