Chemistry · 2026
JEE Main · 8 April 2026, Shift 2 · Q58
Match List - I with List - II. Choose the correct answer from the options given below:
Match List - I with List - II.
Choose the correct answer from the options given below :
| List - I | List - II | |
| Electronic configuration of neutral atom (where $\displaystyle \mathbf{n}=2$ ) | $\displaystyle 1^{\text {st }}$ Ionization Energy ( $\displaystyle \mathbf{k J ~ m o l}^{\boldsymbol{-} \mathbf{1}}$ ) | |
| A. $\displaystyle \mathrm{ns}^2$ | I. | $\displaystyle 2080$ |
| B. $\displaystyle n s^2 n p^1$ | II. | $\displaystyle 899$ |
| C. $\displaystyle n s^2 n p^3$ | III. | $\displaystyle 800$ |
| D. $\displaystyle n s^2 n p^6$ | IV. | $\displaystyle 1402$ |
Official answer
From NTA’s final answer key for this paper.
(1)
A-II, B-III, C-IV, D-I
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.