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Chemistry · 2021

JEE Main · 24 February 2021, Shift 2 · Q50

Match List - I and List - II. Choose the correct answer from the options given below:

Match List - I and List - II.
List - IList - II
(a)2021_JEE-Main_Chemistry_Set_2021-02-24-S2_Subset_Paper-1_Q50___fig1(i)$\displaystyle \mathrm{Br}_2 / \mathrm{NaOH}$
(b)2021_JEE-Main_Chemistry_Set_2021-02-24-S2_Subset_Paper-1_Q50___fig2(ii)$\displaystyle \mathrm{H}_2 / \mathrm{Pd}-\mathrm{BaSO}_4$
(c)2021_JEE-Main_Chemistry_Set_2021-02-24-S2_Subset_Paper-1_Q50___fig3(iii)$\displaystyle \mathrm{Zn}(\mathrm{Hg}) /$ Conc. HCl
(d)2021_JEE-Main_Chemistry_Set_2021-02-24-S2_Subset_Paper-1_Q50___fig4(iv)$\displaystyle \mathrm{Cl}_2$ /Red P, $\displaystyle \mathrm{H}_2 \mathrm{O}$
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.