Chemistry · 2014
JEE Main · 19 April 2014, Shift 1 · Q31
Ionization energy of gaseous Na atoms is 495.5 kJmol^-1. The lowest possible frequency of light that ionizes a sodium atom is (h=6.626 × 10^-34 Js.,…
Ionization energy of gaseous Na atoms is $\displaystyle 495.5 \mathrm{kJmol}^{-1}$. The lowest possible frequency of light that ionizes a sodium atom is $\displaystyle \left(h=6.626 \times 10^{-34} \mathrm{Js}\right.$, $\displaystyle \mathrm{N}_{\mathrm{A}}=6.022 \times 10^{23} \mathrm{~mol}^{-1}$ )
Official answer
(4)
$\displaystyle 1.24 \times 10^{15} \mathrm{~s}^{-1}$
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JEE Main 2014 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.