Chemistry · 2021
JEE Main · 26 February 2021, Shift 2 · Q41
In 1 C H_2= 2 C = 3 C H - 4 C H_3 molecule, the hybridization of carbon 1, 2, 3 and 4 respectively, are:
In $\displaystyle \stackrel{1}{\mathrm{C}} \mathrm{H}_2=\stackrel{2}{\mathrm{C}}=\stackrel{3}{\mathrm{C}} \mathrm{H}-\stackrel{4}{\mathrm{C}} \mathrm{H}_3$ molecule, the hybridization of carbon $\displaystyle 1$, $\displaystyle 2$, $\displaystyle 3$ and $\displaystyle 4$ respectively, are:
Official answer
(3)
$\displaystyle s p^2, s p, s p^2, s p^3$
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.