In Freundlich adsorption isotherm, slope of AB line is:

n with ( $\displaystyle \mathrm{n}, 0.1$ to $\displaystyle 0.5$ )

$\displaystyle \log \mathrm{n}$ with ( $\displaystyle \mathrm{n}>1$ )

$\displaystyle \log \frac{1}{\mathrm{n}}$ with ( $\displaystyle \mathrm{n}<1$ )

$\displaystyle \frac{1}{\mathrm{n}}$ with $\displaystyle \left(\frac{1}{\mathrm{n}}=0\right.$ to $\displaystyle 1 )$