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Chemistry · 2021

JEE Main · 4 August 2021, Shift 1 · Q55

If K_SP of CaSO_4 is 9.0 × 10^-6 at 298 K, the molar solubility of CaSO_4 in 0.2 M Ca ( NO_3)_2 is \ \ \ \ × 10^-6 M. (Nearest integer)

If $\displaystyle \mathrm{K}_{\mathrm{SP}}$ of $\displaystyle \mathrm{CaSO}_4$ is $\displaystyle 9.0 \times 10^{-6}$ at $\displaystyle 298$ K , the molar solubility of $\displaystyle \mathrm{CaSO}_4$ in $\displaystyle 0.2 \mathrm{M} \mathrm{Ca}\left(\mathrm{NO}_3\right)_2$ is \_\_\_\_ $\displaystyle \times 10^{-6} \mathrm{M}$. (Nearest integer)
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