Chemistry · 2022
JEE Main · 24 June 2022, Shift 2 · Q76
Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'.…
Hex-$\displaystyle 4$-ene-$\displaystyle 2$-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is
Official answer
(3)
$\displaystyle 2$-butene
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.