Chemistry · 2019
JEE Main · 11 January 2019, Shift 2 · Q46
A → 4 KOH, O_2 2 B +2 H_2 O (Green) 3 B → 4 HCl 2 C + MnO_2+2 H_2 O (Purple) 2 C → H_2 O, KI 2 A +2 KOH + D In the above sequence of reactions, A and…
$$\underline{\mathrm{A}} \xrightarrow{4 \mathrm{KOH}, \mathrm{O}_2} 2 \underline{\mathrm{~B}}+2 \mathrm{H}_2 \mathrm{O}
$$
(Green)
$$3 \underline{\mathrm{~B}} \xrightarrow{4 \mathrm{HCl}} 2 \underline{\mathrm{C}}+\mathrm{MnO}_2+2 \mathrm{H}_2 \mathrm{O}
$$
(Purple)
$$2 \underline{\mathrm{C}} \xrightarrow{\mathrm{H}_2 \mathrm{O}, \mathrm{KI}} 2 \underline{\mathrm{~A}}+2 \mathrm{KOH}+\underline{\mathrm{D}}
$$In the above sequence of reactions, $\displaystyle \underline{\mathrm{A}}$ and $\displaystyle \underline{\mathrm{D}}$, respectively, are:
Official answer
(2)
$\displaystyle \mathrm{MnO}_2 \text { and } \mathrm{KIO}_3$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.