Chemistry · 2013
JEE Main · 9 April 2013, Shift 1 · Q32
Given: X Na_2 HAsO_3+ Y NaBrO_3+ Z HCl → NaBr + H_3 AsO_4+ NaCl The values of X, Y and Z in the above redox reaction are respectively:
Given :
$$\begin{array}{r}
\mathrm{X} \mathrm{Na}_2 \mathrm{HAsO}_3+\mathrm{Y} \mathrm{NaBrO}_3+\mathrm{Z} \mathrm{HCl} \rightarrow \mathrm{NaBr} \\
+\mathrm{H}_3 \mathrm{AsO}_4+\mathrm{NaCl}
\end{array}
$$
The values of $\displaystyle \mathrm{X}, \mathrm{Y}$ and Z in the above redox reaction are respectively :
Official answer
(3)
$\displaystyle 3, 1, 6$
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JEE Main 2013 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.