Chemistry · 2022
JEE Main · 27 July 2022, Shift 2 · Q82
For a real gas at 25°C temperature and high pressure (99 bar) the value of compressibility factor is 2, so the value of Vander Waal's constant 'b'…
For a real gas at $\displaystyle 25$°C temperature and high pressure ($\displaystyle 99$ bar) the value of compressibility factor is $\displaystyle 2$, so the value of Vander Waal's constant 'b' should be \_\_\_\_
$\displaystyle \times 10^{-2} \mathrm{~L} \mathrm{~mol}^{-1}$ (Nearest integer)
(Given $\displaystyle \mathrm{R}=0.083 \mathrm{~L}$ bar $\displaystyle \mathrm{K}^{-1} \mathrm{~mol}^{-1}$ )
Official answer
25
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.