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Chemistry · 2013
JEE Main 2013 · 2013-04-07 Offline · Q63
Energy of an electron is given by E =-2.178 × 10^-18 J ((Z^2)/(n^2)). Wavelength of light required to excite an electron in an hydrogen atom from…
Energy of an electron is given by $\displaystyle \mathrm{E}=-2.178 \times 10^{-18} \mathrm{~J}\left(\frac{\mathrm{Z}^2}{\mathrm{n}^2}\right)$. Wavelength of light required to excite an electron in an hydrogen atom from level $\displaystyle \mathrm{n}=1$ to $\displaystyle \mathrm{n}=2$ will be :
$$\begin{aligned}
(\mathrm{h} & =6.62 \times 10^{-34} \mathrm{Js} \text { and } \\
\mathrm{c} & \left.=3.0 \times 10^8 \mathrm{~ms}^{-1}\right)
\end{aligned}
$$
Official answer
(2)
$\displaystyle 1.214 \times 10^{-7} \mathrm{~m}$
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JEE Main 2013 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.