Chemistry · 2019
JEE Main · 8 April 2019, Shift 1 · Q45
Diborane ( B_2 H_6) reacts independently with O_2 and H_2 O to produce, respectively:
Diborane $\displaystyle \left(\mathrm{B}_2 \mathrm{H}_6\right)$ reacts independently with $\displaystyle \mathrm{O}_2$ and $\displaystyle \mathrm{H}_2 \mathrm{O}$ to produce, respectively :
Official answer
(3)
$\displaystyle \mathrm{B}_2 \mathrm{O}_3 \text { and } \mathrm{H}_3 \mathrm{BO}_3$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.