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Chemistry · 2022

JEE Main · 27 June 2022, Shift 2 · Q76

Decarboxylation of all six possible forms of diaminobenzoic acids C_6 H_3( NH_2)_2 COOH yields three products A, B and C. Three acids give a product…

Decarboxylation of all six possible forms of diaminobenzoic acids $\displaystyle \mathrm{C}_6 \mathrm{H}_3\left(\mathrm{NH}_2\right)_2 \mathrm{COOH}$ yields three products $\displaystyle \mathrm{A}, \mathrm{B}$ and C . Three acids give a product ' A ', two acids gives a product ' B ' and one acid give a product ' C '. The melting point of product ' $\displaystyle C$ ' is
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.