Chemistry · 2025
JEE Main · 23 January 2025, Shift 2 · Q61
Consider the following reactions K_2 Cr_2 O_7 →[- H_2 O ] KOH [ A ] →[- H_2 O ] H_2 SO_4 [ B ]+ K_2 SO_4 The products [ A ] and [ B ], respectively…
Consider the following reactions
$$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\mathrm{KOH}}[\mathrm{~A}] \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\mathrm{H}_2 \mathrm{SO}_4}[\mathrm{~B}]+\mathrm{K}_2 \mathrm{SO}_4
$$
The products $\displaystyle [\mathrm{A}]$ and $\displaystyle [\mathrm{B}]$, respectively are :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \mathrm{K}_2 \mathrm{CrO}_4 \text { and } \mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.