Chemistry · 2020
JEE Main · 7 January 2020, Shift 2 · Q49
Consider the following reactions: NaCl + K_2 Cr_2 O_7+ H_2 SO_4 →( A )+ side products; (Conc.) (A) + NaOH → (B) + Side products (B) + H_2 SO_4…
Consider the following reactions :
$$\begin{gathered}
\mathrm{NaCl}+\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+\mathrm{H}_2 \mathrm{SO}_4 \rightarrow(\mathrm{~A})+\text { side products }
\text { (Conc.) }
\end{gathered}
$$(A) $\displaystyle +\mathrm{NaOH} \rightarrow$ (B) + Side products
(B)
$\displaystyle +\mathrm{H}_2 \mathrm{SO}_4$ (dilute) $\displaystyle +\mathrm{H}_2 \mathrm{O}_2 \rightarrow(\mathrm{C})+$ Side products
The sum of the total number of atoms in one molecule each of (A), (B) and (C) is
Official answer
18
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.