Chemistry · 2026
JEE Main · 21 January 2026, Shift 1 · Q70
Consider the following reactions. PbCl_2+ K_2 CrO_4 → A +2 KCl (Hot solution) A + NaOH ⇌ B + Na_2 CrO_4; PbSO_4+4 CH_3 COONH_4 →( NH_4)_2 SO_4+ X In…
Consider the following reactions.
$$\mathrm{PbCl}_2+\mathrm{K}_2 \mathrm{CrO}_4 \rightarrow \mathrm{~A}+2 \mathrm{KCl}
$$
(Hot solution)
$$\begin{aligned}
& \mathrm{A}+\mathrm{NaOH} \rightleftharpoons \mathrm{~B}+\mathrm{Na}_2 \mathrm{CrO}_4 \\
& \mathrm{PbSO}_4+4 \mathrm{CH}_3 \mathrm{COONH}_4 \rightarrow\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4+\mathrm{X}
\end{aligned}
$$
In the above reactions, $\displaystyle \mathrm{A}, \mathrm{B}$ and X are respectively.
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \mathrm{PbCrO}_4, \mathrm{Na}_2\left[\mathrm{~Pb}(\mathrm{OH})_4\right] \text { and }\left(\mathrm{NH}_4\right)_2\left[\mathrm{~Pb}\left(\mathrm{CH}_3 \mathrm{COO}\right)_4\right]$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.