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Chemistry · 2021

JEE Main · 25 February 2021, Shift 1 · Q59

Consider the following chemical reaction. CH ≡ CH →[ 2) CO, HCl, AlCl_3] 1) Red hot Fe tube, 873 K Product The number of s p^2 hybridized carbon…

Consider the following chemical reaction. $$\mathrm{CH} \equiv \mathrm{CH} \xrightarrow[\text { 2) } \mathrm{CO}, \mathrm{HCl}, \mathrm{AlCl}_3]{\text { 1) Red hot Fe tube, } 873 \mathrm{~K}} \text { Product } $$ The number of $\displaystyle s p^2$ hybridized carbon atom(s) present in the product is \_\_\_\_.
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.