Chemistry · 2026
JEE Main · 28 January 2026, Shift 2 · Q54
Consider the following aqueous solutions. I. 2.2 g Glucose in 125 mL of solution. II. 1.9 g Calcium chloride in 250 mL of solution. III. 9.0 g Urea…
Consider the following aqueous solutions.
I. $\displaystyle 2.2$ g Glucose in $\displaystyle 125$ mL of solution.
II. $\displaystyle 1.9$ g Calcium chloride in $\displaystyle 250$ mL of solution.
III. $\displaystyle 9.0$ g Urea in $\displaystyle 500$ mL of solution.
IV. $\displaystyle 20.5$ g Aluminium sulphate in $\displaystyle 750$ mL of solution.
The correct increasing order of boiling point of these solutions will be :
[Given : Molar mass in $\displaystyle \mathrm{g} \mathrm{mol}^{-1}: \mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Cl}=35.5, \mathrm{Ca}=40, \mathrm{Al}=27$ and $\displaystyle \mathrm{S}=32$ ]
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \text { I }<\text { II }<\text { III }<\text { IV }$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.