‹ PrevQuestion 233 / 233 · latest first
Offline paper
Chemistry · 2014
JEE Main 2014 · 2014-04-06 Offline · Q38
Consider separate solutions of 0.500 M C_2 H_5 OH ( aq ), 0.100 M Mg_3( PO_4)_2( aq ), 0.250 M KBr ( aq ) and 0.125 M Na_3 PO_4( aq ) at 25°C. Which…
Consider separate solutions of $\displaystyle 0.500$ M $\displaystyle \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}(\mathrm{aq}), 0.100 \mathrm{M} \mathrm{Mg}_3\left(\mathrm{PO}_4\right)_2(\mathrm{aq})$, $\displaystyle 0.250 \mathrm{M} \mathrm{KBr}(\mathrm{aq})$ and $\displaystyle 0.125 \mathrm{M} \mathrm{Na}_3 \mathrm{PO}_4(\mathrm{aq})$ at $\displaystyle 25$°C. Which statement is true about these solutions, assuming all salts to be strong electrolytes ?
Official answer
(1)
They all have the same osmotic pressure.
More from Solutions
- The freezing point of benzene decreases by 0.45^° C when 0.2 g of acetic acid is added to 20 g of benzene. If acetic acid associates to form a dimer…2017
- Elements P and Q form two types of non-volatile, non-ionizable compounds PQ and PQ_2. When 1 g of PQ is dissolved in 50 g of solvent 'A', Δ T_b was…2026
- At 363 K, the vapour pressure of A is 21 kPa and that of B is 18 kPa. One mole of A and 2 moles of B are mixed. Assuming that this solution is ideal,…2021
- Two open beakers one containing a solvent and the other containing a mixture of that solvent with a non volatile solute are together sealed in a…2020
- The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H_2 C_2 O_4 · 2 H_2 O) in 250 mL of water in mol L^-1 is x × 10^-2. The…2021
- Solution A is prepared by dissolving 1 g of a protein (molar mass =50000 g mol^-1 ) in 0.5 L of water at 300 K. Its osmotic pressure is x bar.…2026
- A solution containing 62 g ethylene glycol in 250 g water is cooled to -10^° C. If K_f for water is 1.86 K kg mol^-1, the amount of water (in g)…2019
- 1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio…2019
JEE Main 2014 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.