Chemistry · 2026
JEE Main · 5 April 2026, Shift 1 · Q67
Consider compounds A, B and C with following structural formulae A = CH_3- CH_2- CH_2- CH_2- CH_2- OH; B = CH_2= CH - CH_2- CH_2- CH_3; C = HO -…
Consider compounds $\displaystyle \mathrm{A}, \mathrm{B}$ and C with following structural formulae
$$\begin{aligned}
& \mathrm{A}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH} \\
& \mathrm{~B}=\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3 \\
& \mathrm{C}=\mathrm{HO}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}(\mathrm{OH})-\mathrm{CH}_3
\end{aligned}
$$
For the conversion of B from A , reagent ( D ) required is $\displaystyle \_\_\_\_$ and structural formula of product (E) obtained when C undergoes same reaction using excess reagent (D) is $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
(4)
| D | E |
| Conc. $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ or $\displaystyle \mathrm{H}_3 \mathrm{PO}_4$ | $\displaystyle \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2$ |
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.