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Chemistry · 2019

JEE Main · 10 April 2019, Shift 2 · Q36

Compound A ( C_9 H_10 O ) shows positive iodoform test. Oxidation of A with KMnO_4 / KOH gives acid B ( C_8 H_6 O_4). Anhydride of B is used for the…

Compound $\displaystyle \mathrm{A}\left(\mathrm{C}_9 \mathrm{H}_{10} \mathrm{O}\right)$ shows positive iodoform test. Oxidation of A with $\displaystyle \mathrm{KMnO}_4 / \mathrm{KOH}$ gives acid $\displaystyle \mathrm{B}\left(\mathrm{C}_8 \mathrm{H}_6 \mathrm{O}_4\right)$. Anhydride of B is used for the preparation of phenolphthalein. Compound A is :
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.