Chemistry · 2020
JEE Main · 3 September 2020, Shift 2 · Q36
Complex A has a composition of H_12 O_6 Cl_3 Cr. If the complex on treatment with conc. H_2 SO_4 loses 13.5% of its original mass, the correct…
Complex A has a composition of $\displaystyle \mathrm{H}_{12} \mathrm{O}_6 \mathrm{Cl}_3 \mathrm{Cr}$. If the complex on treatment with conc. $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ loses $\displaystyle 13.5$% of its original mass, the correct molecular formula of A is :
[Given : atomic mass of $\displaystyle \mathrm{Cr}=52 \mathrm{amu}$ and $\displaystyle \mathrm{Cl}=35 \mathrm{amu}$ ]
Official answer
(2)
$\displaystyle \left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl} \cdot 2 \mathrm{H}_2 \mathrm{O}$
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.