Chemistry · 2014
JEE Main · 19 April 2014, Shift 1 · Q46
Nickel (Z=28) combines with a uninegative monodentate ligand to form a diamagnetic complex [ NiL_4]^2-. The hybridisation involved and the number of…
$\displaystyle \operatorname{Nickel}(Z=28)$ combines with a uninegative monodentate ligand to form a diamagnetic complex $\displaystyle \left[\mathrm{NiL}_4\right]^{2-}$. The hybridisation involved and the number of unpaired electrons present in the complex are respectively :
Official answer
(2)
$\displaystyle \mathrm{dsp}^2$, zero
More from Coordination Compounds
- Which of the following complex is octahedral, diamagnetic and the most stable?2023
- The following ligand is:2019
- Which one of the following complexes will consume more equivalents of aqueous solution of Ag(NO_3)?2016
- The conditions and consequence that favours the t_2 g^3 e_g^1 configuration in a metal complex are:2025
- If Ni^2+ is replaced by Pt^2+ in the complex [NiCl_2 Br_2]^2-, which of the following properties are expected to get changed? A. Geometry B.…2023
- To inhibit the growth of tumours, identify the compounds used from the following: A. EDTA B. Coordination Compounds of Pt C. D - Penicillamine D. Cis…2023
- Complex X of composition Cr(H_2 O)_6 Cl_n has a spin only magnetic moment of 3.83 BM. It reacts with AgNO_3 and shows geometrical isomerism. The…2020
- The number of stereoisomers possible for [Co(ox)_2(Br)(NH_3)]^2- is \ \ \ \. [ox = oxalate]2021
JEE Main 2014 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.