Chemistry · 2026
JEE Main · 22 January 2026, Shift 2 · Q53
At T(K), 100 g of 98 % H_2 SO_4( w / w ) aqueous solution is mixed with 100 g of 49 % H_2 SO_4( w / w ) aqueous solution. What is the mole fraction…
At T(K), $\displaystyle 100$ g of $\displaystyle 98 \% \mathrm{H}_2 \mathrm{SO}_4(\mathrm{w} / \mathrm{w})$ aqueous solution is mixed with $\displaystyle 100$ g of $\displaystyle 49 \% \mathrm{H}_2 \mathrm{SO}_4(\mathrm{w} / \mathrm{w})$ aqueous solution. What is the mole fraction of $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ in the resultant solution ?
(Given : Atomic mass $\displaystyle \mathrm{H}=1 \mathrm{u} ; \mathrm{S}=32 \mathrm{u} ; \mathrm{O}=16 \mathrm{u}$ ).
(Assume that temperature after mixing remains constant)
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 0.337$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.