Chemistry · 2022
JEE Main · 27 July 2022, Shift 1 · Q86
At 310 K, the solubility of CaF_2 in water is 2.34 × 10^-3 g / 100 mL. The solubility product of CaF_2 is \ \ \ \ × 10^-8( mol / L )^3. (Give molar…
At $\displaystyle 310$ K , the solubility of $\displaystyle \mathrm{CaF}_2$ in water is $\displaystyle 2.34 \times 10^{-3} \mathrm{~g} / 100 \mathrm{~mL}$. The solubility product of $\displaystyle \mathrm{CaF}_2$ is \_\_\_\_ $\displaystyle \times 10^{-8}(\mathrm{~mol} / \mathrm{L})^3$. (Give molar mass : $\displaystyle \mathrm{CaF}_2=78 \mathrm{~g} \mathrm{~mol}^{-1}$ )
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