Chemistry · 2026
JEE Main · 24 January 2026, Shift 2 · Q55
At 298 K, the mole percentage of N_2( g ) in air is 80 %. Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of N_2(…
At $\displaystyle 298$ K , the mole percentage of $\displaystyle \mathrm{N}_2(\mathrm{~g})$ in air is $\displaystyle 80 \%$. Water is in equilibrium with air at a pressure of $\displaystyle 10$ atm . What is the mole fraction of $\displaystyle \mathrm{N}_2(\mathrm{~g})$ in water at $\displaystyle 298$ K ? ( $\displaystyle \mathrm{K}_{\mathrm{H}}$ for $\displaystyle \mathrm{N}_2$ is $\displaystyle 6.5 \times 10^7 \mathrm{~mm} \mathrm{Hg}$ )
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 9.35 \times 10^{-5}$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.