Chemistry · 2021
JEE Main · 25 July 2021, Shift 1 · Q35
At 298.2 K the relationship between enthalpy of bond dissociation (in kJ mol^-1 ) for hydrogen ( E_H ) and its isotope, deuterium ( E_D ), is best…
At $\displaystyle 298.2$ K the relationship between enthalpy of bond dissociation (in $\displaystyle \mathrm{kJ} \mathrm{mol}^{-1}$ ) for hydrogen $\displaystyle \left(\mathrm{E}_{\mathrm{H}}\right)$ and its isotope, deuterium $\displaystyle \left(\mathrm{E}_{\mathrm{D}}\right)$, is best described by:
Official answer
(2)
$\displaystyle \mathrm{E}_{\mathrm{H}} \simeq \mathrm{E}_{\mathrm{D}}-7.5$
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.